VI. Tablice zmiennych- porpawnosc cwiczenia

#include <iostream>
#include <conio.h>

const short WIELKOSC_TAB = 4;

using namespace std;

int main()
{
    int tab1[ WIELKOSC_TAB ];
    int a, b, c, d;
   
    tab1[ 0 ] = a = 2 + 7 * 16 - 8;
    tab1[ 1 ] = b = 22 * 2 / 11;
    tab1[ 2 ] = c = 8383 - 222 + 292 * 8;
    tab1[ 3 ] = d = 5 * 2 * 4;
   
    cout << "wyniki rownan: " << endl
    << "2 + 7 * 16 - 8 = " << tab1[ 0 ] << endl
    << "22 * 2 : 11 = " << tab1[ 1 ] << endl
    << "8383 - 222 + 292 * 8 = " << tab1[ 2 ] << endl
    << "5 * 2 * 4 = " << tab1[ 3 ] << endl;
   
    getch();
    return( 0 );
}

#include <iostream>
#include <conio.h>

const short WIELKOSC_TAB = 4;

using namespace std;

int main()
{
    int tab1[ WIELKOSC_TAB ];
    int a, b, c, d, e, f, g, h;
   
    tab1[ 0 ] = a = 2 + 7 * 16 - 8;
    tab1[ 1 ] = b = 22 * 2 / 11;
    tab1[ 2 ] = c = 8383 - 222 + 292 * 8;
    tab1[ 3 ] = d = 5 * 2 * 4;
   
    int tab2[ WIELKOSC_TAB ];
   
   
    tab2[ 0 ] = e = a * 2 - 13;
    tab2[ 1 ] = f = b - 4 + 1;
    tab2[ 2 ] = g = c + 88 - 250;
    tab2[ 3 ] = h = d + f + g;
   
   
    cout << "wyniki rownan pierwszej tabeli : " << endl
    << "2 + 7 * 16 - 8 = " << tab1[ 0 ] << endl
    << "22 * 2 : 11 = " << tab1[ 1 ] << endl
    << "8383 - 222 + 292 * 8 = " << tab1[ 2 ] << endl
    << "5 * 2 * 4 = " << tab1[ 3 ] << endl << endl;
   
    cout << "wyniki rownan drugiej tabeli : " << endl
    << "a + * 2 - 13 = " << tab2[ 0 ] << endl
    << "b + - 4 + 1 = " << tab2[ 1 ] << endl
    << "c + 88 - 250 = " << tab2[ 2 ] << endl
    << "d + f + j = " << tab2[ 3 ] << endl;
   
    getch();
    return( 0 );
}